**If** by **'a** **standard** **deck** **of** **cards'** you mean a **52** **card** pack (no Jokers) with 4 suits each of 13 **cards**, **the** **probability** **of** picking a single **card** at random and it being a heart is 13/**52** or 1/4 For a pack with jokers it would be 13/54 Ankit Pal B.E from University of Mumbai (Graduated 2020) 3 y Related. Explanations Question You draw a **card** at random from a **standard** **deck** **of** **52** **cards**. Find each of the following conditional probabilities: **a**) **The** **card** **is** **a** heart, given that it is red. b) The **card** **is** red, given that it is a heart. c) The **card** **is** an ace, given that it is red. d) The **card** **is** **a** queen, given that it is a face **card**. Explanation Verified. In a playing **card** there are **52** **cards**. Therefore the total number of possible outcomes = **52** (**i**) '2' of spades: Number of favourable outcomes i.e. '2' of spades is 1 out of **52** **cards**. Therefore, **probability** **of** getting '2' of spade Number of favorable outcomes P (**A**) = Total number of possible outcome = 1/52 (ii) a jack. But the coin has not changed - if it's a "fair" coin, the **probability** **of** getting tails is still 0.5. Dependent Events Two (or more) events are dependent if the outcome of **one** event affects the outcome of the other(s). Thus, **one** event "depends" on another, so they are dependent. Example I draw two **cards** **from** **a** **deck** **of** **52** **cards**.

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**What is the probability** of ace **card** in a **deck of 52 cards** ? A **card is drawn** from a pack **of 52 cards** . The **probability** of getting an ace is **1**/**52**. View complete answer on byjus.com. What do 4 Aces mean? If you hate your job, then four <b>Aces</b> can mean that something major will happen which will replace your income, allowing you to leave your job. For. Mar 19, 2020 · A **deck** of **standard** **52** **cards** contain four aces. There are four kings in a **standard** **deck** of playing **cards**. So ,we need to find **probability** that **card** **drawn** is either a ace or king i.e. ⇒ . ⇒ . ⇒ . a king or a diamond ; A **deck** of **standard** **52** **cards** contain four kings. There are 13 Diamonds in a **standard** **deck** of playing **cards**. So ,we need to .... TO FIND : **Probability** of the following Total number of **cards** = **52** ( i ) **Cards** which are black king is 2 We know that **PROBABILITY** = = Number of favorable event T otal number of event Hence the **probability** of getting a black king is equal to 2/**52**=1/26 (ii) Total number of black **cards** is 26.. 2017. 6. 10. · A **standard deck** has 13 ordinal **cards** (Ace, 2-10, Jack, Queen, King) with **one** of each in each of four suits (**Hearts**, Diamonds, Spades, Clubs), for a total of #13xx4=**52**# **cards**. If we **draw** a **card from a standard deck**, there are **52 cards** we might get. There are 16 **cards** that will satisfy the condition of picking a Jack, Queen, King, or Ace. This.

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Mar 03, 2021 · A) 1 2 B) 1 **52** C) 1 4 D) 1 13 7) **If one** **card** **is drawn from a standard deck of 52** playing **cards**, **what is the probability** **of drawing** **a heart**? A) 1 4 B) 1 2 C) 3 4 D) 1 8) In a survey of college students, 840 said that they have cheated on an exam and 1795 said that they have not..

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Investigate **cards** in Axie Infinity Universe - best way to theorycraft your Axie abilities! **Draw** a **card** when attacking an Aquatic, Bird, or Dawn target. agl solar boost; locs of love 360; nikon z6 ... A **card is drawn from a standard deck** of **cards what**. Suppose that a **card** **is** **drawn** **from** **a** well-shuffled **deck** **of** **52** **cards**. **What** **is** **the** **probability** **of** drawing each of the following? **a**) **A** queen ... **One** **card** **is** **drawn** **from** an ordinary **deck** **of** **52** **cards**. ... draw a **card** **from** **a** regular **deck** **of** **52** **cards**. **a**. **What** **is** **the** 04:34. You draw a **card** at random from a **standard** **deck** **of** **52** **cards**. Find each of the. Statistics and **Probability**; Statistics and **Probability** questions and answers; 2. **One** **card** **is drawn** **from a standard** **deck** **of 52** playing **cards**. **What is the probability** **of drawing**: a. **a heart** or an odd number? b. a black **card** and an even number? Question: 2. **One** **card** **is drawn** **from a standard** **deck** **of 52** playing **cards**.. You draw two **cards** **from** **a** **standard** **deck** **of** **52** **cards** without replacing the first **one** before drawing the second. **a**. Are the outcomes on the two **cards** independent? Why? b. Find P (3 on the 1stcardand10 on the 2nd). c. Find P (10 on the 1stcardand3 on the 2nd). d. Find the **probability** **of** drawing a 10 and a 3 in either order. 7. Answer by stanbon (75887) ( Show Source ): You can put this solution on YOUR website! **One** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **cards**. **What** **is** **the** **probability** that **card** **is** **a** heart, given that the **card** **is** red? P (heart | red) = P (heart and red)/P (red) = (13/**52**)/ (26/**52**) = 13/26 = 1/2 =================================================. Sep 26, 2019 · answered • expert verified If one card is drawn from a standard 52 card playing deck, determine the probability of getting a jack, a three, a club or a diamond. Round to the nearest hundredth. Please show your work! Thanks! 0.50 0.58 0.65 0.15 garydesir1 is waiting for your help. Add your answer and earn points. This is Expert Verified Answer.

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Example 10 **One** **card** **is** **drawn** **from** **a** well shuffled **deck** **of** **52** **cards**. **If** each outcome is equally likely, calculate the **probability** that **card** will be a diamond Since there **52** **cards** n(S) = Total number of **cards** = **52** There are 13 diamond **cards** Let A be event that diamond **card** **is** withdrawn.

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A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a. **One** **card** **is drawn** **from a standard** **deck** **of 52** **cards**. Find the **probability** **of drawing** **a heart** or a 6.There are 13 hearts and **one** 6 of hearts... 2. Which of the following must be a true statement?... Select **one**: a. The conditional **probability** P(A/B) is the **probability** that event B occurs, knowing A has occurred. b. An event and its complement can .... . Special Euchre **decks** are available, or the **standard** **52**-**card** pack can be stripped to make a **deck** **of** 32 **cards** (**A**, K, Q, J, 10, 9, 8, 7 of each suit), 28 **cards** (7s omitted), or 24 **cards** (7s and 8s omitted). In some games, a joker is added. Object of the Game. The goal is to win at least three tricks.. Example 3: Two **cards** are **drawn** without replacement in succession from a well-shuffled **deck** **of** **52**.

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Transcribed image text: A **single card is drawn from a standard 52**-**card deck**. Let H be the event that the **card drawn** is **a heart**, and let F be the event that the **card drawn** is a face **card**. Find the indicated **probability**. P (H'UF) P(H'UF) = 0 (Type an integer or a simplified fraction.) A **single card is drawn from a standard 52**-**card deck**. **one** less **card** in **the** **deck** because we already had to draw the Heart from the **deck**. Thus: P(Heart and Club) = P (Heart) * P (Club) = 13/**52** * 13/51 = .25 * .255 = .064 We might also have to subtract a value from the numerator as well as the denominator. Try to find the **probability** **of** drawing three red **cards** **from** **a** **deck** without replacement. Question 591370: A single **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** **cards**. Find the **probability** **the** **card** **is**: 1. A red four 2. A heart 3. A 4 or a heart. 4. Not a club. 5. A red or a four 6. A red and a 3 Answer by Edwin McCravy(19211) (Show Source):. **The** **probability** **of** drawing a queen, from a **52** **card** **deck**, **is** 4/52 or 1/13. Wiki User. ∙ 2009-10-09 18:06:35. This answer **is**:. Answer: The **probability** **of** drawing a **card** **from** **a** **standard** **deck** and choosing a king or an ace is (1/13) × (4/51). What is the **probability** **of** drawing a queen of hearts from a **deck** **of** **52** **cards** pinia store.

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Mar 06, 2011 · Number **of **cards in **a deck **= **52 **Number **of **cards that are **heart **= 13 Therefore number **of **cards that are not **heart **= **52**-13 = 39 **Probability of **not **drawing a heart **= 39/**52 **or 3/4 **What is the**.... 2018. 6. 12. · In a **standard deck** of **cards**, there are **52 cards**. They are broken down into suits (4 of them: Spades, **Hearts**, Diamonds, Clubs) of 13 **cards** each. Each suit has 13 ordinal **cards** (A, 2 through 10, Jack, Queen, King). Here we're asked to **draw** a **card** at random and find the **probability of drawing** either a diamond or a 7. Mar 06, 2011 · Number **of **cards in **a deck **= **52 **Number **of **cards that are **heart **= 13 Therefore number **of **cards that are not **heart **= **52**-13 = 39 **Probability of **not **drawing a heart **= 39/**52 **or 3/4 **What is the**....

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**If one** **card** **is drawn** **from a standard** **52** **card** playing **deck**, determine the **probability** of getting a ten, a king or a diamond. Round to the nearest hundredth. # of ways to succeed: 4 + 4 + 13 - 1 -1 = 19. Correct option is D) **Probability** **of** drawing a king = 524= 131 After drawing **one** **card**, **the** number of **cards** are 51. **Probability** **of** drawing aqueen = 514. Now, the **probability** **of** drawing a king and queen consecutively is 131× 514= 6634 Was this answer helpful? 0 0 Similar questions Three **cards** are **drawn** with replacement from a part of **52** **cards**. Calculate the **probability** **of** being dealt a diamond from a **standard** **deck** **of** **52** **cards**. Since there are 4 suits in a **deck** **of** **cards** (hearts, clubs, spades and diamonds) we can find the number of. Transcript. Example 10 **One card is drawn** from a well shuffled **deck of 52 cards**.If each outcome is equally likely, calculate the **probability** that **card** will be a diamond Since there **52 cards** n (S) = Total number of **cards** = **52** There are 13 diamond **cards** Let A be event that diamond **card** is withdrawn So, n (A) = 13 **Probability** of A = P (A.**One card** is selected from a. . Therefore, the proability of drawing a king or 3 is 8/52=2/13. For the second problem, think binomial **probability**. **The** **probability** **of** drawing a king is 1/13. The opposite of at least 1 is none. So, the **probability** **of** getting no kings is 48/52=12/13. We find the **probability** **of** getting no kings and subtract from 1. Also, You should get the same.

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Mar 12, 2011 · **The probability of drawing a **club or **a **nine **from a 52 card deck of standard **playing cards **is **16 / **52 **or approximately 30.8%. There are 13 clubs in **a standard deck of **cards. There are four nines in.... **The** royal flush is a case of the straight flush. It can be formed 4 ways (**one** for each suit), giving it a **probability** **of** 0.000154% and odds of 649,739 : 1. When ace-low straights and ace-low straight flushes are not counted, the probabilities of each are reduced: straights and straight flushes each become 9/10 as common as they otherwise would be.

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winnetka rummage sale 2022; the end netflix; craigslist gmc trucks for sale by owner near Florianpolis State of Santa Catarina; meta computer vision engineer salary; restaurants open till 2am near Panruti Tamil Nadu; Google Algorithm Updates. **The** total number of 8 **card** hands is 52c8, so the **probability** **of** choosing a hand which excludes at least **one** suit is (4 * 39c8 - 6 * 26c8 + 4 * 13c8) / (52c8). You wanted the **probability** that a hand includes every suit which is the opposite of choosing a hand excluding at least **one** suit, and therefore the **probability** that you wanted is. A **standard deck** of playing **cards** had **52 cards**. These **cards** are divided into four 13 **card** suits: diamonds, **hearts**, clubs, and spades. Find the **probability of drawing a heart** or a club at. Let Event B = drawing a red **card**. P (**A**) = 4/52 since there are four aces in each **deck** **of** **52** **cards**. P (B) = 1/2 = 26/**52** since there are four suits and two of them are red (or 26 red **cards** in **a** **deck** **of** **52**) P (A∩B) = the **probability** **of** drawing a red ace = 2/52 since there are 2 red aces in a **deck** **of** **52** **cards**).

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Transcript. Example 10 **One card is drawn** from a well shuffled **deck of 52 cards**.If each outcome is equally likely, calculate the **probability** that **card** will be a diamond Since there **52 cards** n (S) = Total number of **cards** = **52** There are 13 diamond **cards** Let A be event that diamond **card** is withdrawn So, n (A) = 13 **Probability** of A = P (A.**One card** is selected from a. **A** **standard** **deck** **of** **cards** has: **52** **Cards** in 13 values and 4 suits ... If you draw 3 **cards** **from** **a** **deck** **one** at a time what is the **probability**: ... what is the **probability**: You draw a Club, a Heart and a Diamond (in that order). The hypergeometric MTG calculator can describe the likelihood of any number of successes when **drawing** from a **deck** of Magic **cards**. It takes into account the fact that each **draw** decreases the size of your library by **one**, and therefore the **probability** of success changes on each **draw**. Population Size. **Cards** in your **deck** / library you are **drawing** from.

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Number of favourable outcomes = 48 (Because There are always **52** **cards** in **one** **deck** containing 13 **cards** **of** varying values but always 4 suits, if the **drawn** **card** **is** not 4 then number of favourable outcomes will be 48 (12*4).) Total number of favourable outcomes = **52** (Number of **cards** in **a** **deck** **is** **52**) So, the **probability** will be = 48/ **52** = 12/13. Oct 26, 2020 · Answer: 1/13. Step-by-step explanation: If there are 4 suits in a **deck** of **cards**, there are only 4 aces inside a complete **deck**. That means **the probability of drawing** an ace is 4/**52** and just simply simplify the answer to 1/13.. **A** SINGLE **CARD** **IS** **DRAWN** AT RANDOM FROM A **STANDARD** **DECK** **OF** **52** **CARDS**. FIND THE **PROBABILITY** **OF** DRAWING THE FOLLOWING **CARDS**. PLEASE REDUCE TO LOWEST TERMS. **A**) **A** DIAMOND OR A 5 __________ B) A HEART AND A JACK __________ C) A JACK OR AN 8 __________ D) A HEART OR A SPADE __________ E) A RED AND FACE **CARD** __________ F) A RED **CARD** OR A QUEEN __________ 2. A **standard deck** of playing **cards** had **52 cards**. These **cards** are divided into four 13 **card** suits: diamonds, **hearts**, clubs, and spades. Find the **probability of drawing a heart** or a club at. Suppose you draw five **cards** **from** **a** **standard** **deck** **of** **52** playing **cards**, and you want to calculate the **probability** that all five **cards** are hearts. ... For example, the **probability** **of** drawing five **cards** **of** any **one** suit is the sum of four equal probabilities, and four times as likely. In boolean language, if the events are related by a logical OR. Whenever you do **probability** problems, check to see if you are being asked to find **probability** **of** **one** thing OR another, or of multiple events happening together. For instance, if this problem asked you to find the **probability** **of** drawing a heart AND a 5, well, there is only **one** 5 of hearts in a **deck**. So that would be 1/52.

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This can be simplified into 4/13 or a 30.77% **probability** **of drawing** a 4 or a spade **from a standard** **deck** of **cards**. Read More:. After an ace **is drawn** on the first **draw**, there are 3 aces out of 51 total **cards** left. This means that the conditional **probability** **of drawing** an ace after **one** ace has already been **drawn** is 3 51 = 1 17 3 51 = 1 17.. A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a. a **card is drawn from a standard deck what is the probability** that the **card** is an ace If you **draw one card from a standard deck**, **what is the probability of drawing** a 5 ... a **deck** of **cards** there are four suits of 13 **cards** each. The four suits are: **hearts**, diamonds, clubs, and spades. The 26 **cards** included in **hearts** and Tìm kiếm.

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2022. 2. 7. · We know that a well-shuffled **deck** has **52 cards**. Total number of black **cards** = 26. Total number of red **cards** = 26. Therefore **probability** of getting a black **card**= {total number. 5) If **one** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**, **what** **is** **the** **probability** **of** drawing an ace? **A**) 1 13 B) 1 **52** C) 1 4 D) 1 2 6) If **one** 39,068 satisfied customers 2,852 satisfied customers Ph.D. 39,068 satisfied customers the **probability** for the experiment of drawing a **card** at random from a **standard** **deck** **of** **52** playing **cards**. **What is the probability** **of drawing** a black checker from a bag filled with 6 black checkers and 4 red checkers, replacing it, and **drawing** another black checker? c. Getting a Club and **a Heart** . 2. **Drawing** a **card** from a **deck** and not replacing it. 1.. So, there are 12 face **cards** in the **deck** **of 52** playing **cards**. Worked-out problems on Playing **cards** **probability**: 1. A **card** **is drawn** from a. A **card** is selected from a **deck** **of 52** playing **cards**. Find the **probability** of selecting · a prime number under 10 given the **card** is **a heart**. (1 is not prime.) · a diamond or **heart** given the **card** is red. read ....

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**A** **card** **is** randomly **drawn** **from** **a** **standard** **52**-**card** **deck**. Find the **probability** **of** **the** given event. (**A** face **card** **is** **a** king, queen, or jack). Drawing a queen and a heart (this is an intersection question). A **card is drawn** randomly **from a standard 52**-**card deck**.Find the **probability** of the given event. (a) The **card drawn** is 6 The **probability** is:(b) The **card drawn** is a face **card** (Jack, Queen, or King) The read more.Solution Total number of possible outcomes = **52** P (E) = (Number of favourable outcomes/ Total number of outcomes) (i) Total numbers of the king of. Since we know that in a **deck** **of** **52** **cards**, there are a total 12 face **cards** (3 face **cards** each of heart, diamond, spade and club). Number of face **cards**$ = 12$ Therefore, **probability** **of** getting a face **card**$ = \dfrac { { {\text {Number of face **cards**}}}} { { {\text {Total number of **cards**}}}} = \dfrac { {12}} { {**52**}} = \dfrac {3} { {13}}$. Jun 21, 2020 · **If one** **card** **is drawn** **from a standard** **52**-**card** playing **deck**, find the **probability** of getting a king, or a ten, or **a heart**, or a club.When entering your answer include a leading zero and round to the nearest hundredth. An example of an acceptable answer would be 0.19. Question 591370: A single **card** **is drawn** **from a standard** **deck** **of 52 cards. Find the probability the card** is: 1. A red four 2. **A heart** 3. A 4 or **a heart**. 4. Not a club. 5. A red or a four 6. A red and a 3 Answer by Edwin McCravy(19211) (Show Source):. Jun 21, 2020 · **If one** **card** **is drawn** **from a standard** **52**-**card** playing **deck**, find the **probability** of getting a king, or a ten, or **a heart**, or a club.When entering your answer include a leading zero and round to the nearest hundredth. An example of an acceptable answer would be 0.19.

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The total number of **cards** in a **deck** is **52 Probability** = No. of favorable outcomes / Total no. of outcomes. Now, the **probability** of **cards** in a **deck** is 13/ **52** . Understand different concepts and get good grip on them by using online tools available at.

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A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a. Apr 26, 2017 · Ace is not odd The ordinals 3, 5, 7, and 9 are odd. There are four of each (**one** for each suit) and so 4xx4=16 odd **cards**. This makes the **probability**: P("**draw** an odd **card**")=16/**52**=4/13 Ace is odd If we want to consider the Ace as a 1, then there are 5 ordinals that are odd, 5xx4=20 odd **cards**, and therefore: P("**draw** an odd **card**")=20/**52**=5/13.

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There are **5 2 cards** in a **standard deck**: **1** 3 ordinal **cards** (Ace - **1** 0, Jack, Queen, King) and 4 of them - **one** to each suit (**hearts**, diamonds, clubs, spades) and so we have 4 × **1** 3 = **5 2**.. Q. From a pack of **52** playing **cards** jacks, queens, kings and aces of red colour are removed. From the remaining, a **card** **is** **drawn** at random. Find the **probability** that **the** **card** **drawn** **is** (**i**) **a** black queen (ii) a red **card** (iii) a black jack (iv) a picture **card** (Jacks, queens and kings are picture **cards**). Step 2. ∵ number of non-face **card** in well shuffled **deck** **of** **52** playing **card** = **52**-12. = 40. Step 3. **Probability** ( a non-face **card** ) = number of favourable outcomes total number of outcomes. = 40 **52**. = 10 13. Step 4. (ii) Number of black king in well shuffled **deck** **of** **52** playing **cards** = 2. Mar 06, 2011 · Number **of **cards in **a deck **= **52 **Number **of **cards that are **heart **= 13 Therefore number **of **cards that are not **heart **= **52**-13 = 39 **Probability of **not **drawing a heart **= 39/**52 **or 3/4 **What is the**....

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The goal is to win at least three tricks.. Example 3: Two **cards** are **drawn** without replacement in succession from a well-shuffled **deck** **of 52** playing **cards**. **What is the probability** that the second **card** **drawn** is an ace, given that the first **card** **drawn** was an ace? Example 4: **One** thousand high school seniors were surveyed about whether they planned .... Problem 2: A random **card** is chosen from the **standard** **deck** of **cards**, find the **probability** of obtaining a queen or **a heart**.. So, the **probability** of getting a Queen **card** is 1/13. Example 2: A **card** **is drawn** from a well-shuffled pack **of 52** **cards**. Find the **probability** of getting a **card** of **Heart**. Solution: Let A represents the event of getting **a Heart** .... A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a. **A** **standard** **deck** **of** **cards** has: **52** **Cards** in 13 values and 4 suits ... If you draw 3 **cards** **from** **a** **deck** **one** at a time what is the **probability**: ... what is the **probability**: You draw a Club, a Heart and a Diamond (in that order).

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Number of Kings in a **deck** = 4. **Probability of drawing a card from a standard deck and choosing a** king or an ace = **Probability** of getting an Ace + **Probability** of getting a King. **Probability of drawing** an Ace at random = 4/**52** = **1**/13. Now, the **probability of drawing** a King at random = 4/**52** = **1**/13. hence, the required **probability** = **1**/13 + **1**/13 = 2/13. **What** **is** **the** **probability** **of** drawing a heart from a **standard** **deck** **of** **cards** on a second draw? 2 Answers By Expert Tutors The **probability** **of** choosing a heart, P(Heart) = 13/**52** = 0.25. What is the **probability** **of** getting a heart or an even number? Clearly, the **probability** **of** drawing a heart out of the **deck** **is** 13/**52**, or 1/4.. "/>.

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**If one** **card** **is drawn** **from a standard** **52** **card** playing **deck**, determine the **probability** of getting a ten, a king or a diamond. Round to the nearest hundredth. # of ways to succeed: 4 + 4 + 13 - 1 -1 = 19. This means there are four Aces, four Kings, four Queens, four 10s, etc., down to four 2s in each **deck**.You **draw** two **cards from a standard deck of 52 cards** without replacing the first **one** before **drawing** the second. (a) Are the outcomes on the two **cards** independent? Why? No. The events cannot occur together. No. The **probability of drawing** a. Here’s another way to break. A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a. **one** less **card** in **the** **deck** because we already had to draw the Heart from the **deck**. Thus: P(Heart and Club) = P (Heart) * P (Club) = 13/**52** * 13/51 = .25 * .255 = .064 We might also have to subtract a value from the numerator as well as the denominator. Try to find the **probability** **of** drawing three red **cards** **from** **a** **deck** without replacement. There are 6 red face **cards** in a **standard deck of 52 cards**; the Jack, Queen, and King of **Hearts** and Diamonds.The **probability**, then, **of drawing** a red face **card from a standard deck of 52 cards** is 6 in **52**, or 3 in 26, or about 0.1154.. Exactly half of the **cards** are even.Thus, your odds of getting an even number are 26/**52** = 50% If you wish to exclude the face **cards** from the. Given, **one card is drawn** from a well-shuffled **deck of 52 cards** Total number of **cards** $ = **52** $ As we know that the general formula for **probability** is given by **Probability** of occurrence of an event $ = \dfrac { { {\text {Number of favorable outcomes}}}} { {. **The** **probability** **is** 0.000240. A STRAIGHT This is five **cards** in a sequence (e.g., 4,5,6,7,8), with aces allowed to be either 1 or 13 (low or high) and with the **cards** allowed to be of the same suit (e.g., all hearts) or from some different suits. The number of such hands is 10*[4-choose-1]^5. The **probability** **is** 0.003940. **If one** **card** **is drawn** **from a standard** **52** **card** playing **deck**, determine the **probability** of getting a ten, a king or a diamond. Round to the nearest hundredth. # of ways to succeed: 4 + 4 + 13 - 1 -1 = 19.

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**The** **probability** **is** 0.000240. A STRAIGHT This is five **cards** in a sequence (e.g., 4,5,6,7,8), with aces allowed to be either 1 or 13 (low or high) and with the **cards** allowed to be of the same suit (e.g., all hearts) or from some different suits. The number of such hands is 10*[4-choose-1]^5. The **probability** **is** 0.003940.

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This **deck** of **cards** comes in three different formats: **Deck** of **Standard Cards** - **52** playing **cards** plus 2 jokers, perfect for any games requiring the use of playing **cards** ! **Deck** of Many Things - This legendary item has a maximum of 22 **cards** , each with their own magical effects. **Deck** of Illusions - This wonderous item can be found in a full set of 32 **cards**.

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**A** common topic in introductory **probability** **is** problems involving a **deck** **of** **standard** playing **cards**. These can be handy if you are playing **card** games or just trying to understand **probability**. ... A **standard** **deck** **of** **cards** contains **52** different **cards**. It contains **cards** **of** 13 different ranks, ranging from Ace (essentially 1) through 10, followed by.

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Statistics and **Probability**; Statistics and **Probability** questions and answers; 2. **One** **card** **is drawn** **from a standard** **deck** **of 52** playing **cards**. **What is the probability** **of drawing**: a. **a heart** or an odd number? b. a black **card** and an even number? Question: 2. **One** **card** **is drawn** **from a standard** **deck** **of 52** playing **cards**.. **A** **card** **is** **drawn** **from** **a** pack of **52** **cards**. **The** **probability** **of** getting a queen of club or a king of heart is 1/13 2/13 1/26 1/52 Answer: Option C Explanation: Total number of cases = **52** Favourable cases = 2 **Probability** = 2/56 = 1/26 Similar Questions : 1. In a throw of coin what is the **probability** **of** getting tails. 1 2 1/2 0 Answer: Option C. Question 591370: A single **card** **is drawn** **from a standard** **deck** **of 52 cards. Find the probability the card** is: 1. A red four 2. **A heart** 3. A 4 or **a heart**. 4. Not a club. 5. A red or a four 6. A red and a 3 Answer by Edwin McCravy(19211) (Show Source):. **A** **card** **is** **drawn** **from** **standard** **deck** **of** playing **cards**. ... and king of hearts. Thus there is a **probability** **of** $3/52$ of picking a **card** that **is** **a** heart and a face **card** $\endgroup$ - WaveX. Apr 18, 2019 at 13:00. Add a comment ... Assume draw that you draw a **card** **from** **a** **standard** **deck**.Find the **probability** **of** drawing a heart Given that your drew a. **A** **card** **is** randomly **drawn** **from** **a** **standard** **52**-**card** **deck**. Find the **probability** **of** **the** given event. (**A** face **card** **is** **a** king, queen, or jack). Drawing a queen and a heart (this is an intersection question). The total number of **cards** in a **deck** is **52 Probability** = No. of favorable outcomes / Total no. of outcomes. Now, the **probability** of **cards** in a **deck** is 13/ **52** . Understand different concepts and get good grip on them by using online tools available at. (A **standard** **deck** of **cards** is the most common type of **deck** used in most **card** games containing **52** **cards**). Determine the **probability** of having 1 girl and 3 boys in a 4-child family assuming boys and girls are equally likely. The **probability** of having 1 girl and 3 boys is 1/4. Use the theoretical method. **Probability** gives the chances of how likely .... **A** **standard** **deck** **of** **cards** **is** **a** common sample space used for examples in **probability**. **A** **deck** **of** **cards** **is** concrete. In addition, a **deck** **of** **cards** possesses a variety of features to be examined. This sample space is simple to understand, but yet can be utilized for a number of different kinds of calculations. It is helpful to list of all of the. There are 13 heart **cards** in **a** **standard** **deck** **of** **52** **cards** so **the** **probability** **of** drawing a heart is 13/**52**. This can be simplified into 1/4 or a 25% **probability** **of** getting a heart **card** in **a** **deck** **of** **cards**. How many 4 of hearts in a **deck** **of** **cards**? There is only **one** 4 of hearts in a **52** **card** **deck**. **Card** Table lets you and up to 3 friends play your favorite **card** games with a virtual **deck of 52 cards**.You need an iPad to run the game and an iPhone or iPod touch for each player. The iPad acts like a **card** table, and is home to the **deck** of **cards**.Players keep their **cards** on their iPhone or iPod, which becomes their virtual hand... valley view apts. Mar 12, 2011 · **The probability of drawing a **club or **a **nine **from a 52 card deck of standard **playing cards **is **16 / **52 **or approximately 30.8%. There are 13 clubs in **a standard deck of **cards. There are four nines in.... a **card is drawn from a standard deck what is the probability** that the **card** is an ace If you **draw one card from a standard deck**, **what is the probability of drawing** a 5 ... a **deck** of **cards** there are four suits of 13 **cards** each. The four suits are: **hearts**, diamonds, clubs, and spades. The 26 **cards** included in **hearts** and Tìm kiếm.

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This means there are four Aces, four Kings, four Queens, four 10s, etc., down to four 2s in each **deck**.You **draw** two **cards from a standard deck of 52 cards** without replacing the first **one** before **drawing** the second. (a) Are the outcomes on the two **cards** independent? Why? No. The events cannot occur together. No. The **probability of drawing** a. Here’s another way to break.

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Example 10 **One** **card** **is** **drawn** **from** **a** well shuffled **deck** **of** **52** **cards**. **If** each outcome is equally likely, calculate the **probability** that **card** will be a diamond Since there **52** **cards** n(S) = Total number of **cards** = **52** There are 13 diamond **cards** Let A be event that diamond **card** **is** withdrawn.

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Statistics and **Probability**; Statistics and **Probability** questions and answers ; **Probability** with a **Deck** of **Cards** These questions are based on a **52 card deck** without Jokers. **1** ) Find the **probability of drawing** a face **card** that is a Diamond. A **card is drawn from a standard deck of 52** playing **cards**. A: The result is a 7. B: The result is a jack. Playing **cards probability** problems based on a well-shuffled **deck of 52 cards**. Basic concept on **drawing** a **card**: In a pack or **deck of 52** playing **cards**, they are divided into 4 suits of 13 **cards** each i.e. spades ♠ **hearts** ♥, diamonds ♦,. Two **cards** are **drawn** successively and without replacement from an ordinary **deck** **of** playing **cards** Compute the **probability** **of** drawing. **a**. Two hearts. b. A heart on the first draw and a club on the second draw. c. A heart on the first draw and an ace on the second draw. Jun 21, 2020 · **If one** **card** **is drawn** **from a standard** **52**-**card** playing **deck**, find the **probability** of getting a king, or a ten, or **a heart**, or a club.When entering your answer include a leading zero and round to the nearest hundredth. An example of an acceptable answer would be 0.19.

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Jun 21, 2020 · **If one** **card** **is drawn** **from a standard** **52**-**card** playing **deck**, find the **probability** of getting a king, or a ten, or **a heart**, or a club.When entering your answer include a leading zero and round to the nearest hundredth. An example of an acceptable answer would be 0.19. **If one** **card** **is drawn** **from a standard** **52** **card** playing **deck**, determine the **probability** of getting a ten, a king or a diamond. Round to the nearest hundredth. # of ways to succeed: 4 + 4 + 13 - 1 -1 = 19. Therefore, 12 C **1** (Selecting **1** out of 12 items) times out **of 52** C **1** ( Selecting **1** out **of 52** items) a face **card** is picked. Let, E 2 be the event of getting a face **card** from pack. By using the formula for **probability**, we get. P ( E 2) = 12 C **1 52** C **1** = 12 **52** = 3 13. Hence, the **probability** of getting a face **card** is 3 13. Apr 26, 2017 · If the Ace isn't odd, 4/13. If the Ace is odd, 5/13 In a **standard deck** of **cards**, there are 13 ordinals: 9 numbered **cards** 2-10, plus **cards** Jack, Queen, King, and Ace (which could.

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Dec 22, 2021 · Carson flips over the **cards** of a **standard** **52** -**card** **deck** **one** at a time. **What is the probability** that he flips over the ace of spades before any face **card** (jack, queen or king)? asked Jul 8 in Data Science & Statistics by ♦ MathsGee Platinum ( 132,618 points) | 31 views. Question: If **one** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards** **what** **is** **the** **probability** **of** drawing a heart? 1 3/4 1/2 1/4 This problem has been solved! See the answer Show transcribed image text Expert Answer 80% (5 ratings) d)1/4 (135)∗ (41) (525) (135)∗ (41) (525) 1down voteaccepted It w View the full answer. 4/**52** x 4/**52**. **Probability** you **draw** a 6 then a 10 W/OUT replacement. 4/**52** x 4/51. **probability** you **draw** a black 7 and a red 4 WITH replacement. 2/**52** x 2/**52**. **probability** you **draw** a black 7 and a red 4 W/OUT replacement. 2/**52** x 2/51. **probability** that we **draw** a jack and a king WITH replacement. 4/**52** x 4/**52**..

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Expert Answer. Transcribed image text: A **single card is drawn from a standard 52**-**card deck**. Find the conditional **probability** that the **card** is **a heart**, given that it is a king, The **probability** that the **card drawn** is **a heart**, given that it is a king is (Type an integer or a fraction) A **single card is drawn from a standard 52**-**card deck**. In a playing **card** there are **52** **cards**. Therefore the total number of possible outcomes = **52** (**i**) '2' of spades: Number of favourable outcomes i.e. '2' of spades is 1 out of **52** **cards**. Therefore, **probability** **of** getting '2' of spade Number of favorable outcomes P (**A**) = Total number of possible outcome = 1/52 (ii) a jack. Answer and Explanation: 1 We are asked to find the **probability** **of** drawing a heart from a **standard** **deck** **of** **52** playing **cards**. Thus, the total sample is **52**. **52**. In **a** **standard** **deck**, there are 13. **The** royal flush is a case of the straight flush. It can be formed 4 ways (**one** for each suit), giving it a **probability** **of** 0.000154% and odds of 649,739 : 1. When ace-low straights and ace-low straight flushes are not counted, the probabilities of each are reduced: straights and straight flushes each become 9/10 as common as they otherwise would be.

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Mar 12, 2011 · **The probability of drawing a **club or **a **nine **from a 52 card deck of standard **playing cards **is **16 / **52 **or approximately 30.8%. There are 13 clubs in **a standard deck of **cards. There are four nines in....

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Apr 26, 2017 · If the Ace isn't odd, 4/13. If the Ace is odd, 5/13 In a **standard deck** of **cards**, there are 13 ordinals: 9 numbered **cards** 2-10, plus **cards** Jack, Queen, King, and Ace (which could.

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Total number of **cards** = **52 One card is drawn** randomly. Step 2 P(face **card**):-Number of favourable outcomes = 12 (Face **card**) P( face **card** ) = 12 **52** = 3 13 P(not face **card**) = **1** − (3 13) = 10 13 To convert **probability** to odds divide the **probability** by **1** - that **probability** Odds in favor **of drawing** a face **card** are 3 13 10 13 = 3: 10 Odds in favor.

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1.Two **cards** are picked randomly, with replacement, from a regular **deck** **of** **52** playing **cards**. 12 **cards** are court cards(C), and 40 **cards** are spot cards(S). Draw a tree diagram to list all possible outcomes and their corresponding probabilities. 2.The letters of the word 'SUCCESS' are printed on 7 **cards**. Jacob chooses a **card** at random, replaces. This page allows you to **draw** playing **cards** from randomly shuffled **decks** using true randomness, which for many purposes is better than the pseudo-random number algorithms. A **standard 52 card deck**. If two **cards** are randomly selected, **what is the probability of drawing** a king first, followed by **drawing** a 2. If two **cards** are randomly selected **what is the probability of drawing a heart** first, followed by **drawing** a.

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Question: **If one card is drawn** at random **from a standard deck** of **cards** , **what is the probability of drawing** a queen. toyota land cruiser rear shock replacement; check cashing store west palm beach.

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Special Euchre **decks** are available, or the **standard** **52**-**card** pack can be stripped to make a **deck** **of** 32 **cards** (**A**, K, Q, J, 10, 9, 8, 7 of each suit), 28 **cards** (7s omitted), or 24 **cards** (7s and 8s omitted). In some games, a joker is added. Object of the Game. The goal is to win at least three tricks.. Example 3: Two **cards** are **drawn** without replacement in succession from a well-shuffled **deck** **of** **52**. Given, **one card is drawn** from a well-shuffled **deck of 52 cards** Total number of **cards** $ = **52** $ As we know that the general formula for **probability** is given by **Probability** of occurrence of an event $ = \dfrac { { {\text {Number of favorable outcomes}}}} { {. In this task, we need to calculate the **probability** **of** getting at least **one** black **card**. **The** given is that we draw 2 2 2 **cards** **from** **a** **52** **52** **52**-**card** **deck** with replacement.. The **deck** **is** **the** **standard** **deck** with 4 4 4 suits, clubs, spades, hearts, and diamonds, where spades and clubs are black suits. Jun 21, 2020 · **If one** **card** **is drawn** **from a standard** **52**-**card** playing **deck**, find the **probability** of getting a king, or a ten, or **a heart**, or a club.When entering your answer include a leading zero and round to the nearest hundredth. An example of an acceptable answer would be 0.19. Sep 19, 2020 · **The **answer should be 3/**52 **Step-by-step explanation: There are 12 face cards and 3 **of the **face cards are hearts. Advertisement Advertisement New questions in Mathematics Mr Thompson drew **a **rectangle on **the **chalk board with **a **length to width ratio 5 to 2 he asked students to draw **a **rectangle with **the **same ratio **of **lengt h to width in their journals..

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Therefore, the proability of drawing a king or 3 is 8/52=2/13. For the second problem, think binomial **probability**. **The** **probability** **of** drawing a king is 1/13. The opposite of at least 1 is none. So, the **probability** **of** getting no kings is 48/52=12/13. We find the **probability** **of** getting no kings and subtract from 1. Also, You should get the same.

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. Let Event B = drawing a red **card**. P (**A**) = 4/52 since there are four aces in each **deck** **of** **52** **cards**. P (B) = 1/2 = 26/**52** since there are four suits and two of them are red (or 26 red **cards** in **a** **deck** **of** **52**) P (A∩B) = the **probability** **of** drawing a red ace = 2/52 since there are 2 red aces in a **deck** **of** **52** **cards**). Jan 13, 2017 · There is a 50% chance that the **card** **drawn** will be red. Red **cards** make up 50% of the **deck**. 26/**52** = 1/2 Therefore, if you're **drawing** **one** **card**, there is a 50/50 chance that the **card** will be red..

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**A** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. **A**: **The** result is a club. B: The result is a king. 36) A **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. Find the **probability** that **the** **card** **is** an ace or a king. 37) A **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. Find the **probability** that **the** **card** **is** an ace or a black **card**. We can draw **one** **card** **from** pack of **52** **cards** in 52C1 = **52** ways n (S)=52 There is only **one** **card** in the pack of **52** **cards** which is jack as well as heart card,.It is jack of hearts n (E)=1 DIY: How to take years off your neck's appearance. Ray Phan Principal Software Engineer at Magic Leap (company) (2021-present) 4 y Related. Jan 13, 2017 · There is a 50% chance that the **card** **drawn** will be red. Red **cards** make up 50% of the **deck**. 26/**52** = 1/2 Therefore, if you're **drawing** **one** **card**, there is a 50/50 chance that the **card** will be red.. Problem 2: A random **card** is chosen from the **standard** **deck** of **cards**, find the **probability** of obtaining a queen or **a heart**.. So, the **probability** of getting a Queen **card** is 1/13. Example 2: A **card** **is drawn** from a well-shuffled pack **of 52** **cards**. Find the **probability** of getting a **card** of **Heart**. Solution: Let A represents the event of getting **a Heart** .... 5) If **one** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**, **what** **is** **the** **probability** **of** drawing an ace? **A**) 1 13 B) 1 **52** C) 1 4 D) 1 2 6) If **one** 39,068 satisfied customers 2,852 satisfied customers Ph.D. 39,068 satisfied customers the **probability** for the experiment of drawing a **card** at random from a **standard** **deck** **of** **52** playing **cards**. Correct option is D) **Probability** **of** drawing a king = 524= 131 After drawing **one** **card**, **the** number of **cards** are 51. **Probability** **of** drawing aqueen = 514. Now, the **probability** **of** drawing a king and queen consecutively is 131× 514= 6634 Was this answer helpful? 0 0 Similar questions Three **cards** are **drawn** with replacement from a part of **52** **cards**. In this task, we need to calculate the **probability** **of** getting at least **one** black **card**. **The** given is that we draw 2 2 2 **cards** **from** **a** **52** **52** **52**-**card** **deck** with replacement.. The **deck** **is** **the** **standard** **deck** with 4 4 4 suits, clubs, spades, hearts, and diamonds, where spades and clubs are black suits.

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**If** you were investigating red **cards**, kings or the queen of hearts, the odds of randomly drawing **one** **of** these from a complete **deck** are 50 percent (26 in **52**); about 7.7 percent (four in **52**); or. **One** **card** is randomly **drawn** from a **deck** **of 52** playing **cards**. Find the **probability** thati the **drawn** **card** is red.ii the **drawn** **card** is an ace.iii the **drawn** **card** is red and a king.iv the **drawn** **card** is red or a king.[4 MARKS]. **A** **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. **A**: **The** result is a club. B: The result is a king. 36) A **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. Find the **probability** that **the** **card** **is** an ace or a king. 37) A **card** **is** **drawn** **from** **a** **standard** **deck** **of** **52** playing **cards**. Find the **probability** that **the** **card** **is** an ace or a black **card**. Setup **Card** content **One card** per line. Supports basic HTML. Go!. You will come across many video chatting applications, but a few of the best ones that are very effective and perfect for a virtual **card** room are Zoom and Skype. With Zoom, you can add around 100 people; however, the session will only last for 45minutes, and you will have to start.

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Jan 13, 2017 · There is a 50% chance that the **card** **drawn** will be red. Red **cards** make up 50% of the **deck**. 26/**52** = 1/2 Therefore, if you're **drawing** **one** **card**, there is a 50/50 chance that the **card** will be red.. Playing **cards probability** problems based on a well-shuffled **deck of 52 cards**. Basic concept on **drawing** a **card**: In a pack or **deck of 52** playing **cards**, they are divided into 4 suits of 13 **cards** each i.e. spades ♠ **hearts** ♥, diamonds ♦,. A **standard deck** of playing **cards** had **52 cards**. These **cards** are divided into four 13 **card** suits: diamonds, **hearts**, clubs, and spades. Find the **probability of drawing a heart** or a club at random from a **deck** of shuffled **cards**. math. A **card is drawn** from an ordinary **deck of 52 cards**, and the result is recorded on paper.

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2010. 6. 4. · There are 6 red face **cards** in a **standard deck of 52 cards**; the Jack, Queen, and King of **Hearts** and Diamonds. The **probability**, then, **of drawing** a red face **card from a standard deck of 52 cards** is 6 in **52**, or 3 in 26, or about 0.1154. (A **standard** **deck** of **cards** is the most common type of **deck** used in most **card** games containing **52** **cards**). Determine the **probability** of having 1 girl and 3 boys in a 4-child family assuming boys and girls are equally likely. The **probability** of having 1 girl and 3 boys is 1/4. Use the theoretical method. **Probability** gives the chances of how likely ....